# Learn Tips And Tricks To Crack Quantitative Aptitude Section from the IBPS PO Question Paper 2016

### Solved IBPS PO Question Paper 2016 with tips and tricks to save a lot of time and boost your score in IBPS PO 2017

Quantitative Aptitude Section of IBPS PO exam is one of the most time-consuming sections of the IBPS PO Exam. It is mandatory for you to learn all the speed math techniques to perform calculations and various operations to crack the quantitative aptitude section of  IBPS PO Exam.

In this post, we will discuss IBPS PO Question Paper 2016 and solve the aptitude questions using the speed math techniques.

IBPS PO Question Paper 2016 - Question 1

Direction: Study the following table and answer the questions that follow.

IBPS PO Question Paper 2016- Data Interpretation Question 1:
What is the average invalid votes for village A for the given years (approximate)?

1)400           2) 425           3) 450           4) 375           5) 350

Solution:
Step 1: Find the total number of invalid votes for the village A for the given years
For year 2000: 2500 – 2250 = 250
For year 2005: 3800 – 3250 = 550
For year 2010: 3400 – 3000 = 400

250 + 550 + 400
= 1200 (Use Unit Digit Method to Calculate)

Step 2:
Average invalid votes = Total number of invalid votes/ Total number of years
1200/ 3 = 400

Therefore, the correct answer is option 1) 400

IBPS PO Question Paper 2016- Data Interpretation Question 2:
If total vote polled in village B in the year 2000, 25% polled by females and total valid female votes are 1875 then, find the number of valid votes polled by males?

1) 5675          2) 5825          3) 5450          4) 5950          5) 5725

Solution:
Step 1:
Number of valid votes polled by males of the village B = Total number of valid votes in the year 2000, polled by the village B – Total number of valid votes by females of village B in the year 2000

Step 2:
By substituting the values in the above formula,
Number of valid vote votes polled by males of the village B
= 7600 – 1875
= 5725 (Use Split and Merge Method to Calculate)

Therefore, the correct answer is option 5) 5725.

IBPS PO Question Paper 2016- Data Interpretation Question 3:
What is the average of valid votes polled in the year 2000?

1) 4750          2) 4600          3) 4850          4) 4700          5) 5150

Solution:
Step 1:
Total valid votes for the year 2000 for Village A, B and C is
2250 + 7600 + 4250 = 14100

Step 2:
Average valid votes for the year 2000 for Village A, B and C is
Total valid votes for the year 2000 for Village A, B and C/ Total Number of villages
14100/ 3
= 4700

Therefore, the correct answer is option 5) 4700.

IBPS PO Question Paper 2016- Data Interpretation Question 4:
Total votes of village A in 2000 is what percent of valid votes polled in village C in  2010?
1) 29%          2) 35%          3) 37%          4) 42%          5) 44%

Solution: (This is question from percentages)
Step 1:
x is what percentage of y = (x/ y) x 100
x is Total votes of village A in 2000
y is Total valid votes of villages C in 2010

Step 2:
By substituting the values in the above formula,
(2500/ 6750) x 100
= 37%

Therefore, the correct answer is option 3) 37%.

IBPS PO Question Paper 2016- Data Interpretation Question 5:
Valid votes polled in village C in 2005 is by what percent less than total votes polled in village B in 2000?

1) 39.50%          2) 42.50%          3) 46.75%          4) 41.25%          5) 37.75%

Solution: (This is question from percentages)
Step 1:
x is what percentage less/more than y
[(x – y)/ y] x 100
Valid votes polled in village C in 2005 = x
Total votes polled in village B in 2000? = y

Step 2:
By substituting the values in the above formula,
[(4600 – 8000)/ 8000] x 100
(3400/ 8000) x 100
= 42.50

Therefore, the correct answer is option 2) 42.50%

IBPS PO Question Paper 2016: Question 2:
Find the probability that a number from 1 to 300 is divisible by 3 or 7?

1) 37/75          2) 32/75          3) 36/75          4) 28/75          5) 26/75

Solution:
Step 1:
P(3) = 3/ 300 = 100
P(7) = 7/ 300 = 42

Step 2:
P(3 or 7) = 300/ 21 = 14

Probability = Favorable events/ total number of events
(100 + 42 – 14)/ 300
= 128/ 300

= 32/75

Therefore, the correct option is 2) 32/75.

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