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In this post, we will discuss all the tangent formulas that will help you solve circle questions and save time in SSC CGL Exam.

In this post, we will discuss all the tangent formulas that will help you solve circle questions and save time in SSC CGL Exam.

Questions from geometry section, especially circle questions always appear in SSC Exams. These Circle Questions can be easily solved with the help of formulas.

This is the third post in the series of Circles. In this post, we will discuss tangent formulas that will help you solve circle questions easily and thus help you save time during SSC Exams.

This is the third post in the series of Circles. In this post, we will discuss tangent formulas that will help you solve circle questions easily and thus help you save time during SSC Exams.

### What Is A Tangent?

A tangent is a line that touches the circle exactly at one point on the circumference of a circle.### What Is A Secant?

Secant is a line that touches the circumference or cuts the circumference of the circle at two points.

**List of Tangent Formulas to Solve Circle Questions**

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**Tangent Formula 1: **

The angle between the tangent and the radius of the circle at the point of contact is 90 degrees.

### Tangent Formula 2:

This property is based on the Length of a tangent:1. The length of two tangents from an external point is equal in length.

2. Tangent Formula to measure the length of a chord

Let's take the distance between the centre and the point P as ‘d’ At the point of contact, where the radius and tangent meet 90 degree - right angle is formed. Now we get two right angled triangles.

OAP and OBP are right angled triangles. Hence, by using Pythagoras theorem, we know that OA is the radius, OP is the distance and AP is the hypotenuse. Therefore, hypotenuse AP which is the tangent can be found by:

**√d² - r²**

### Tangent Formula 3:

This tangent formula is based on a tangent and a secant.
1.There is a circle, from external point P we draw a tangent and a secant.

PT is the length of the tangents and TBA is the length of the secant. Therefore,**PT² = PA x PB**

Hence, When we draw a tangent and secant from an external point then, the length of the tangent square will be equal to PA and PB

2. When we draw two secant lines, suppose PAB and PCD then,

2. When we draw two secant lines, suppose PAB and PCD then,

**PA x PB = PC x PD**

Have a look at chord formulas too, to have a firm grip over circle questions.

Hope these tangent formulas have been of help to you while preparing for SSC CGL 2017 as circle questions often appear in these competitive exams.

Do write in the comment section below on how these Tangent Formulas have helped you solve circle questions asked in mock tests for SSC CGL. Also, download free questionnaire for practice!

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Do write in the comment section below on how these Tangent Formulas have helped you solve circle questions asked in mock tests for SSC CGL. Also, download free questionnaire for practice!

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