Friday, 12 May 2017

Simplification III – Simplification Questions solved using Unit Digit Method

In this post, we will discuss Unit Digit Method to solve Simplification Questions for IBPS PO and SSC CGL Exams
Simplification Questions

Do huge simplification questions scare you in IBPS PO and SSC CGL Exams? Do you often tend to skip these questions due to large calculations? Here we are with a simple yet smart method which will help you to solve simplification questions in IBPS PO and SSC CGL Exams within 10 to 15 seconds.

In our previous post Simplification I- Simplification Tricks to solve Simplification Problems and Simplification II- Simplification Questions for IBPS PO and SSC CGL Exam we have solved few Simplification Questions using the smart method.In this post, we will discuss the unit digit method which will help you to find the answers through smart ways.

Unit digit Method
Unit digit method is a method in which we find the solution by taking the unit digits of the numbers and try to find the unit digit of the answer which will help us eliminate options in IBPS PO and SSC CGL Exams. Unit digit method works only with Addition, Subtraction and Multiplication. We cannot find the solution through unit digit method for Division.
Simplification Questions


Simplification Questions

Simplification Questions

Example 8: Simplification Questions for IBPS PO and SSC CGL Exams

Question:
(12 x 19) + (13 x 8) = (15 x 14) - ?
1) 124   2) 122   3)126   4)128   5) None of these

Solution:
Step 1:
First, start with multiplying the unit digits in the brackets, to calculate the answer-
(12 x 9) = 9 x 2 = 8
(13 x 8) = 3 x 8 = 4
(15 x 14) = 0

Step 2:
Now as we know the unit digits of the answer, we can balance the equation to find the unit digit of the unknown value-
8 + 4 = 0 - ?
The unit digit of the right-hand side equation is 2
2 = 0 - ?
? = 2

Step 3:
As we now know the unit digit of the unknown value we can start eliminating the options one by one.
Option 1 is not the correct answer as it doesn’t end with 2.
Option 2 is the suitable answer as it ends with 2.
Option 3 is not the correct answer as it doesn’t end with 2.
Option 4 is not the correct answer as it doesn’t end with 2.
Option 5 none of these can be the correct answer as we don’t know the whole number.

Step 4:
After cutting down the options we now have Option 2 and Option 5 which can be the suitable answers. There is 50% chance of them being correct. In exams such as IBPS PO and SSC CGL Exam, it is important that we save our time. So, we are supposed to make a calculated guess. You can either choose the option 2 or option 5 whichever option you feel to be correct. In IBPS PO and SSC CGL Exam, we need to take the risks, as we have limited time. But, here we select option 2 and move on. The choice is up to you to solve the whole problem and spend a minute in it or solve it in few seconds and move on by taking the risk.

Therefore, the answer is option 2: 122
Simplification Questions
Example 9: Simplification Questions for IBPS PO and SSC CGL Exams

Question:
?² + 65² = 160² - 90² - 7191
1) 75    2)77   3)79   4) 81   5)None of these.

Solution:
Step 1:
This question appears to be tough but it can be solved in 5 to 10 seconds through the unit digit method in IBPS PO and SSC CGL Exam.
Now finding the square root is a tough task,
So just see the digit of the unit place and perform the operations as follow,
?² + 5 = 0 - 0 -1 ( as we need to borrow a digit from the tens place)
?² + 5 = 9
?² = 9 – 5
?² = 4

Step 2:
As we know that unit place of the unknown value we can start eliminating the options.
Option 1 is not the correct answer as it doesn’t end with 4.
Option 2 is not the correct answer as it doesn’t end with 4.
Option 3 is not the correct answer as it doesn’t end with 4.
Option 4 is not the correct answer as it doesn’t end with 4.
Option 5 none of these is the correct answer as other option doesn’t satisfy the condition.

Therefore, the correct answer is option 4: None of these.

Example 10: Simplification Questions for IBPS PO and SSC CGL Exams

Question:
398 x ? x 7 = 47362
1) 15   2)13    3)17   4)19  5) None of these

Solution:
Step 1:
By using the unit digit method, we can get the unit digit of the unknown value which will help you to eliminate the options.
First, multiply the unit digits-
By multiplying 8 x 7 we get the unit digit as 6.
Now-
6 x  ? = 2 ( as L.H.S = R.H.S)

Step 2:
Multiply 6 with the unit digit of the options to get the unit digit as 2.
For example, by multiplying 6 with option 1 of the unit digit i.e. 5 we get 0. So, option 1 is not eligible to be the answer, we eliminate it.
Likewise,
6 x 3 = 8 ; option 2 eliminated
6 x 7 = 2 ; option 3 satisfies our requirement
6 x 9 = 4 ; option 4 eliminated.
Option 5; none of these can be our answer too.

Step 3:
Now that we know option 2 and option 5 can be our answer. The option which highly seems to be correct can be marked. Though there are 50% chances of it being wrong, In IBPS PO and SSC CGL we cannot afford to waste time, just mark the answer and move on instead of solving the entire sum. Again the choice is yours.

Therefore, the answer is Option 3: 17

Example 11: Simplification Questions for IBPS PO and SSC CGL Exams

Question:
Simplification Questions
 1)181/331    2)164/441   3)155/246    5)161/241

Solution:

This question is time-consuming. It takes around two and half minute to solve this question. The smart way to solve this simplification question is to leave the question. Move on to the next question and come back to this question at the end when the time is left. 

Do write down in the comment section, how this post helped you to solve these Simplification Question for IBPS PO and SSC CGL Exam and Save Time.

Stay tuned for more Simplification Questions. 
Simplification Questions 
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