**In this post, we will discuss mixtures and alligation questions and solve them using formulas in IBPS PO Exam**

In this post, we will focus on formulas that will help you solve Mixtures and alligation questions easily and also use the pictorial method of representation which will make it easy for you to understand the question and solve them without any trouble.

**What is a Mixture?**

A

**mixture**contains two or more ingredients of certain of certain quantity mixed together to get the desired quantity. The quantity can be expressed as ratios or percentage.
When two varieties of rice are mixed to form a new variety of rice then it is called as a mixture.

**What is an Alligation?**

If two ingredients A and B of price x and y respectively are mixed and the price of the resultant mixture is M (mean price)then the ratio (R) in which ingredients are mixed is given by,

**the rule of the alligation**

An

**alligation**is the rule that enables us to find the ratio in which two or more ingredients at a given price or value must be mixed to produce a mixture at a given price (Value or Strength).

**Formulas for Mixtures and alligation questions for IBPS PO Exam.**

**Pictorial representation of Mixtures and Alligation**

**Model 1: Mixtures and Alligation**

**Example 1**:

**Mixtures and Alligation Questions for IBPS PO Exam**

**Question:**How much of salt at 42 paise/kg must be mixed with 25kg of salt at 24 paise/kg, so that a profit of 25% is obtained by selling the mixture at 40 paise /kg?

**Solution:**

Th question is based on a combination of two different varieties of salt to obtain a mixture at the given price.

In this question, we are suppose to find the quantity of salt which costs 42 paise that is mixed.

So, we need to find the ratios of the quantity to find the quantity of salt that is mixed.

**Step 1:**

First, we need to find the price of the mixed salt, that is

Profit = 25%

Selling Price = 40 paise/kg

Cost of the Mixture = 32 paise

**Step 2:**

The ratio = 4 : 5

Quantity(dearer) : Quantity (Cheaper) = 4 : 5

Quantity(dearer) : 25 = 4 : 5

Quantity(dearer) x 5 = 4 x 25

Quantity(dearer) = 100/5

Quantity(dearer) = 20kg

Therefore, The 20kg of dearer quantity is supposed to be mixed with 25kg of cheaper quantity to make a new mixture of salt.

**Example 2: Mixtures and Alligation Questions for IBPS PO Exam**

**Question:**A merchant has 840kg of rice, part of which he sells at 9% profit and the rest at 16% profit. He must gain 12% profit on the whole. What is the quantity sold at 16% profit?

**Solution:**

**Step 1:**

By applying the alligation rule on the profit percentages

**Step 2:**

Quantity (sold at 9% profit): Quantity (sold at 16% profit) = 4 : 3

840: Quantity (sold at 16% profit) = 4 : 3

Quantity (sold at 16% profit) = (3 / 7) x 840 (by the basis of ratio and proportion, we need to take the whole part i.e. 4 + 3 = 7)

Quantity (sold at 16% profit) = 360Kg.

Therefore, 360Kg is the quantity that is sold at 16% profit.

Do write in the comment section how this blog helped you to solve mixtures and alligation questions using mixture and alligation formula.

Stay tuned for more mixtures and alligation questions.

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