###
**There is no running away from logical reasoning questions when you want to crack competitive exams like IBPS PO Exam. Questions on Numeric Series can be very scoring if approached the right way.**

Logical Series are of many kinds, and questions on most of them are asked in IBPS PO Exam . Honestly, the logical reasoning section is not very difficult but what makes it very challenging is the limited amount of time that you have to solve these questions. In the previous post about reasoning question, Logical Series I- Logical Reasoning Questions for IBPS PO Exam, we discussed logical reasoning concepts that involve a series of mathematical operations. In the second article in this series, we will once again discuss logical reasoning questions, but those that involve number series.

It is would be a great idea to go through the concepts used to solve logical reasoning questions on mathematical operators before you move to logical reasoning questions on numeric series.

###
**Set I –Numeric Series Based Logical Reasoning Questions**

In such reasoning questions, there are a series of three digit numbers followed by a question. The questions are based on logical reasoning and need you to follow some simple steps to get the answer.

**Problem 1**

**:**If the position of the first and the third digits in each of the numbers are interchanged, which of the following will be the third number?

1) 851 2) 743 3) 624 4) 319 5) 298

**Solution 1:**

The 1

^{st}and the 3^{rd}digits of all the five numbers have to be interchanged, doing that we get-
Once we have all the numbers we can arrange them in the descending order-

From the above table, we can conclude that ‘426’ is the 3

^{rd}highest number which is obtained from ‘624’.
Therefore the answer is Option 3- 624

**Smart Solution:**

Reasoning questions of the same kind can be solved by a quicker method by using a very simple concept of logical reasoning.

The simple logical reasoning trick this question being that once the 3

^{rd}and the 1^{st}digit are interchanged, the 3^{rd}digit actually becomes the 1^{st}digit.
We know a number is higher or lower based on the digit at the hundreds place, as these are all three digit numbers.

So from all the digits in the units place, whichever is third highest, will be the answer. So we arrange them in the descending order-

So the third highest number is the number with 4 in it, which is 624.

So by this method, most of the steps involve logical reasoning will actually be done mentally and you will have to write almost nothing on the paper and will reach the correct answer in less than 5 seconds!

**Problem 2**

**:**If in each of the below numbers, the digits are arranged in ascending order, what will be the sum of the middle digits of all the numbers?

1) 19 2) 14 3) 17 4) 21 5) None of these

**Solution 2:**

So we need to start by arranging the digits in the numbers in ascending order, so all the numbers now become-

Now we have to add their middle digits-

Adding the numbers we get,

2 + 4 + 2 + 6 + 3 = 17

Therefore the answer is Option 3- 17

**Smart Solution:**

Using logical reasoning smartly, the same question can we solved by writing negligible steps and doing most calculations mentally.

So we need to start by just identifying the 2

^{nd}highest digit in each number and then adding them-
Simply by adding we get the answer-

2 + 4 + 2 + 6 + 3 = 17

###
**Logical Reasoning Practice Questions on Numeric Series**

Question 1: If in each number, the digits are arranged in ascending order, what will be the sum of the middle digits of each of the numbers?

1) 14 2) 12 3) 26 4) 17 5) None of these

Question 2: Which of the following numbers will be obtained if the second digit of the lowest number is added to the third digit of the highest number after adding 4 to each number?

1) 5 2) 6 3) 7 4) 8 5) None of these

## 0 comments:

## Post a Comment