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**There is no running away from logical
reasoning questions when you want to crack competitive exams like IBPS PO, SBI
PO and SSC CGL. Questions on Numeric Series can be very scoring if approached
the right way.**

Logical Series
are of many kinds, and questions on most of them are asked in IBPS PO, SBI PO and SSC CGL. Honestly the logical reasoning section is not very difficult but
what makes it very challenging is the limited amount of time that you have to
solve these questions. In the previous post about reasoning question, Logical
Series I- Logical Reasoning Questions for Bank and SSC Exams, we discussed
logical reasoning concepts that involve a series of mathematical operations. In
the second article in this series, we will once again discuss logical reasoning
questions, but those that involve number series.

It is would
be a great idea to go through the concepts used to solve logical reasoning
questions on mathematical operators before you move to logical reasoning
questions on numeric series.

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**Set I –Numeric Series Based Logical
Reasoning Questions**

In such reasoning
questions there are a series of three digit numbers followed by a question. The
questions are based on logical reasoning and needs you to follow some simple
steps to get the answer.

**Problem 1**

**:**If the position of the first and the third digits in each of the numbers are interchanged, which of the following will be the third number?

1) 851 2) 743
3) 624 4) 319
5) 298

**Solution 1:**

The 1

^{st}and the 3^{rd}digits of all the five numbers have to be interchanged, doing that we get-
Once we have
all the numbers we can arrange them in the descending order-

From the above
table we can conclude that ‘426’ is the 3

^{rd}highest number which is obtained from ‘624’.
Therefore
the answer is Option 3- 624

**Smart Solution:**

Reasoning questions
of the same kind can be solved by a quicker method by using a very simple
concept of logical reasoning.

The simple
logical reasoning trick this question being that once the 3

^{rd}and the 1^{st}digit are interchanged, the 3^{rd}digit actually becomes the 1^{st}digit.
We know a
number is higher or lower based on the digit at the hundreds place, as these
are all three digit numbers.

So from all
the digits in the units place, whichever is third highest, will be the answer.
So we arrange them in the descending order-

So the third
highest number is the number with 4 in it, which is 624.

So by this
method, most of the steps involve logical reasoning will actually be done
mentally and you will have to write almost nothing on the paper and will reach
the correct answer in less than 5 seconds!

**Problem 2**

**:**If in each of the below numbers, the digits are arranged in ascending order, what will be the sum of the middle digits of all the numbers?

1) 19 2) 14
3) 17 4) 21
5) None of these

**Solution 2:**

So we need
to start by arranging the digits in the numbers in ascending order, so all the
numbers now become-

Now we have
to add their middle digits-

Adding the
numbers we get,

2 + 4 + 2 +
6 + 3 = 17

Therefore
the answer is Option 3- 17

**Smart Solution:**

Using
logical reasoning smartly, the same question can we solved by writing
negligible steps and doing most calculations mentally.

So we need
to start by just identifying the 2

^{nd}highest digit in each number and then adding them-
Simply by
adding we get the answer-

2 + 4 + 2 +
6 + 3 = 17

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**Logical Reasoning Practice Questions
on Numeric Series**

Question 1: If
in each number, the digits are arranged in ascending order, what will be the
sum of the middle digits of each of the numbers?

1) 14 2) 12 3) 26 4) 17 5) None of these

Question 2:
Which of the following numbers will be obtained if the second digit of the
lowest number is added to the third digit of the highest number after adding 4
to each number?

1) 5 2) 6 3) 7 4) 8 5) None of these

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