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**Logical Reasoning Questions are an inseparable
part of every Bank and SSC Exam, therefore as an aspirant for these jobs, it
becomes almost mandatory for you to get command over this topic. **

Logical reasoning
questions from logical series are not only fun and challenging but also an
integral part of exams like IBPS PO, SBI PO and SSC CGL. With a little practice
and knowledge of few hacks logical reasoning questions can be solved in just a
few seconds! They are pretty much capable to making a difference to your score
and taking you through the cut off. In a two series blog post on logical reasoning
questions we will discuss logical reasoning questions that are based on
mathematical operators and those reasoning questions that are based on number
series.

Before we
start discussing logical reasoning questions based on mathematical operators,
you must go through the 5 tricks that will help you maximize your score in the
logical reasoning section.

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**Set I – Mathematical Operations Logical
Reasoning Questions**

Of the
various kind of logical reasoning questions asked in IBPS PO, SBI PO and SSC
CGL, the most commonly asked ones are about mathematical operations. Such
logical reasoning questions need you to perform various mathematical operations
based on the conditions specified to get to the answer.

**Problem 1**

**:**If A is followed by B then C-

**Question 1:**

If P is the
resultant of the first row, what will be the resultant of the second row?

**Solution 1:**

Based on the
5 conditions that have been given, we have to find the resultant of the 2

^{nd}row. To find the resultant of the 2^{nd}row, we first have to find the value of P, which is the resultant of the 1^{st}row. To find the resultant of the 1^{st}row, we have to do nothing but simply follow the conditions and perform the required mathematical operations.
Let us start
with the first two numbers- 15 and 8

15 is an odd
number, so we refer to conditions (i), (iv) and (v), since 8 is an even number
we will refer to condition (v).

So we need
to subtract 8 from 15-

15 – 8 = 7

Now the next
pair of number we have to deal with are- 7 and 21

7 is an odd
number, so we refer to conditions (i), (iv) and (v), as 21 is a composite odd
number we will refer to condition (i).

So we need
to add 21 to 7-

7 + 21 = 28

28 is the resultant
of the first row and the value of P.

Now we move
to the 2

^{nd}row with the value of P as 28.
28 is an
even number, so we refer to conditions (ii) and (iii), since 3 is an odd number
we will refer to condition (ii).

So we need
to add 28 to 3-

28 + 3 = 31

Moving on to
the next pair of numbers- 31 and 27

31 is an odd
number, so we go back to conditions (i), (iv) and (v), since 27 is an odd number
we will refer to condition (i).

So we need
to add 31 to 27-

31 + 27 = 58

Therefore,
the answer, the resultant of the 2

^{nd}row is 58.
This how
logical reasoning questions can be easily solved by just following the steps.

**Question 2:**

If r is the
resultant of the first row, what will be the resultant of the second row?

**Solution 2:**

Based on the
5 conditions that have been given, we have to find the resultant of the 2

^{nd}row. To do that we first have to find the value of r, this is nothing but the resultant of the 1st row.
Starting
with the first two numbers- 85 and 17

85 is an odd
number, so we refer to conditions (i), (iv) and (v), since 17 is an odd prime number
we will refer to condition (iv).

So we need
to divide 85 to 17-

85 + 17 = 5

Now the next
pair of numbers we have to deal with are- 5 and 35

Once again 5
is an odd number, so we refer to conditions (i), (iv) and (v), since 35 is a
composite odd number we will refer to condition (i).

So we need
to add 5 and 35-

5 + 35 = 40

Since 40 is
the resultant of the 1st row, it will also be the value of r.

Now the next
pair of numbers is- 19 and 16

As 16 is an
even number, we have to use the (ii) and (iii) condition; also since 19 is an odd
number, the condition we have to refer to here is (ii).

So we need
to add 16 and 19-

16 + 19 = 35

The next
pair of numbers is – 35 and 40

35 is an odd
number, we have to use the so we refer to conditions (i), (iv) and (v), since
40 is an even number we will refer to condition (v).

So we need
to subtract 40 from 35-

35 - 40 = -5

Hence, the
answer is -5.

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**Logical Reasoning Questions for
Practice**

Directions
(1-2): In each of the following questions, two rows of numbers are given. The
resultant numbers are given. The resultant number in each row is to be worked
out separately based on the following rules and the questions below the rows of
numbers are to be answered. The operations of numbers progress from the left to
right.

Rules:

i) If an odd
number is followed by another composite odd number, they are to be added

ii) If an even
number is followed by an odd number they are to be added.

iii) If an
even number is followed by a number which is the perfect square, the even
number is to be subtracted from the perfect square.

iv) If an
odd number is followed by a prime odd number the first number is to be divided
by the second number.

v) If an odd
number is followed by an even number, the second one is to be subtracted from
the first number.

Question 1:
15 8 21

P 3 27

If ‘P’ is the resultant of the first row, what will be the resultant of second row?

P 3 27

If ‘P’ is the resultant of the first row, what will be the resultant of second row?

1) 58 2) 76 3) 27 4) 82 5) None of these

Question 2:
12 64 17

20 m 16

If ‘m’ is the resultant of the first row, what will be the resultant of second row?

20 m 16

If ‘m’ is the resultant of the first row, what will be the resultant of second row?

1) 69 2) 85 3) 101 4) 121 5) None of these

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