**Reasoning Tricks that help you in decoding codes can fetch you marks in less time in all Bank and SSC Exams. Read on as we decode the different kinds of codes and how to solve questions based on them.**

Coding and
Decoding is an integral topic in Reasoning Section of all competitive exams
where usually 3 to 8 questions are asked from this topic. However, solving
these questions without some reasoning tricks can be very difficult and time
taking. It is therefore advisable, that you get some reasoning tricks up your
sleeves that help you to solve questions in least amount of time.

In this post
we will not only discuss- what is coding and decoding, different ways in which coding
and decoding is done, reasoning tricks that will help you identify the codes
and finally practice questions to use the reasoning tricks discussed.

###
**Introduction to Reasoning Tricks-
What is Coding and Decoding?**

Coding and
Decoding basically means sending out information in a coded manner to someone
so that the people involved in transferring this information are not able to
understand it. However, the person to whom the information is transferred is
able to decode it using some reasoning tricks. This method of transferring
information was extremely popular during both the World Wars and till much
later, till technology finally took over use of these reasoning tricks.

###
**Understanding Different Kind of
Reasoning Tricks- Decoding the Codes**

There are
infinite reasoning tricks that are use to write codes, which means you can get
various kinds of questions based on coding and decoding. We shall discuss some
very popular reasoning tricks that will help you decipher codes and solve
questions based on it.

The image
below shows how different reasoning tricks have been used to write codes for
the word – “

**Let’s now decode these codes and learn some reasoning tricks while doing the same.***BANK”.*####
**Reasoning Tricks 1: Symbol based
Coding**

When codes are
written using symbols, in that case each symbol represents a letter in the word
that has been coded. Like in this case,

B = @

A = #

N = $

K = %

So once we
find the codes for each of these symbols, we can find the code for any word.

**Reasoning Tricks 2: Shifting the Position Forward**

In this form
of codes, every letter in the word is represented by another letter. From the
code below you can observe-

B = C

A = B

N = O

K = L

The logic
behind this kind of coding is shifting of letters; in this case letters have
been shifted in the forward direction. The letter which comes after

**‘B’**is**‘C’,**the letter which comes after**‘A’**is**‘B’**and so on. So each letter has been shifted by +1 in the alphabetical order. In a similar manner, letters can be shifted forward by 2, 3 or even more positions.####
**Reasoning Tricks 3: Shifting the
Position Backward**

When codes
are written like this, every letter is once again represented by another
letter. From this code we know-

B = A

A = Z

N = M

K = J

This coded
form is very similar to the previous one, because once again shift of positions
has happened; only this time letters have been shifted backwards. We know as
per alphabetical order

**‘A’**comes before**‘B’,****‘Z’**comes before**‘A’**and so on, for the remaining part of the word. As you see, each letter has seen a shift of -1 in its position in the code. Similarly, while using reasoning tricks like this, letters can be shifted backwards any number of positions.####
**Reasoning Tricks 4: Alternate
Shifting Form **

Codes are
often written in a manner to confuse you and throw you off guard. This coding
decoding example is a clear example of this -

B = A

A = B

N = M

K = L

Once again
positions of letters have been changed in codes, but they are a mixture of
forward and backward positions. You will notice

**‘B’**is replaced by**‘A’**and A comes before B. On the other hand,**‘A’**is replaced by**‘B’**, and B comes after A. So, the first letter has been moved backwards while the second letter has been moved forward. Similarly, for the 3^{rd}and 4^{th}letters,**‘N’**is replaced by**‘M’**which is one ahead and**‘K’**is replaced by**‘L’**which is one backwards. Therefore positions of letters are shifted alternately in this method of coding and decoding and this shift can be of any number of units.####
**Reasoning Tricks 5: Position Based
Increase **

The way to
code that we will discuss now, may look a little complicated, but once you
crack the reasoning tricks behind it, it becomes really simple!

B = C

A = C

N = Q

K = O

Now notice
carefully, ‘B’ is moved
ahead by +1 since it comes

**‘C’, ‘A’**is moved ahead by +2 as it becomes**‘C’, ‘N’**is moved ahead by +3 and it comes**‘Q’**and finally**‘K’**becomes**‘O’**as it is moved ahead by +4. S if you notice, each alphabet has moved ahead in the code by the number of positions, depending on its position in the word that has been coded. Therefore, the increase with every position can vary in patterns too.####
**Reasoning Tricks 6: Numeric Position
in Alphabetical Order**

You don’t
need to get sacred every time you see a word coded in numbers because these
reasoning tricks used in coding and decoding is really simple. The number
denotes the position of the letter in the alphabetical order.

B = 2

A = 1

N = 14

K = 11

We know

**‘B’**comes 2nd in the series of alphabets,**‘A’**comes 1st,**‘N’**comes at the 14th position and**‘K’**comes at the 11th position. All these numbers are simply written in the same order and this code is achieved. Similarly, any word can be coded by just writing its numeric position in the alphabetical order. To get hold of such reasoning tricks, it is almost mandatory that you learn the numeric positions of alphabets in the alphabetical order.###
**Reasoning Tricks 7: Numeric Positions
in Reverse Alphabetical Order**

The logic
behind this is really simple! As the name suggests the numbers suggest the
position of the letters, but only in the reverse order. So as per this method
of coding and decoding,

**‘Z’**becomes 1 and**‘A’**becomes 26.
B = 25

A = 26

N = 13

K = 16

So if we
know the positions of letters in alphabetical order, it becomes easy to find their
position in the reverse order. When discussing the topic of ‘Ranking’, in
Reasoning Ability we discussed that when we know the position of one element
from one end, we can easily find the position of the element from the other end
too by using a simple formula-

T = Total Number of Elements, P = Position from the given
End

This formula can also be used to find the position of the
letters in the reverse order. Let’s start with the letter

**‘A’**and see how this formula simplifies reasoning tricks for us-**A’**= Position of A in the reverse order, using the formula we get –

**A’**= 26 - 1 + 1

**A’**= 26

Similarly we
can try for

**B’ , C’**and any other alphabet.**B’**= 26 - 2 + 1 = 25

**C’**= 26 – 3+ 1 = 24

By using
this formula for the letters ‘N’ and ‘K’, we get the code- 25261316

###
**Reasoning Tricks 8: Reverse
Alphabetical Order**

The logic for
this code is very similar to the previous one. As the name implies, the letters
in the code are those letters which are at the same numeric position when the
reverse alphabetical order is taken.

B = Y

A = Z

N = M

K = P

So as per
this method of coding and decoding,

**‘B’**comes at the 25^{th}position and therefore it becomes**‘Y’**,**‘A’**comes at the 26^{th}position and therefore it becomes**‘Z’**, similarly**‘N’**becomes**‘M’**and**‘K’**becomes**‘P’.**###
**Reasoning Tricks 9: Sum of Positions**

This kind of
coding is very interesting, the 4 letter word a reduced to a 2 digit number. It
is actually the sum of positions of the letters in alphabetical order.

B = 2

A = 1

N = 14

K = 11

Adding the
numeric positions of these alphabets, we get

2 + 1 + 14 +
11 = 28

Similarly, any
word can be coded by summing up the position of the letters in the word.

####
**Reasoning Tricks 10: Product of
Positions**

This method
of coding is not very different from the previous method of coding because this
also deals with the positions of letters in the alphabetical order.

B = 2

A = 1

N = 14

K = 11

Multiplying
the numbers that denote the positions of the letters, we get –

2 x 1 x 14 x
11 = 308

In a similar
manner, any word can be coded by taking the product of its position.

####
**Reasoning Tricks 11: Average of
Positions**

This unique
method of coding again uses a mathematical operation, and the operation used
here is- Average. An average is taken of the positions of the letters in the
word.

B = 2

A = 1

N = 14

K = 11

We know
average is equal distribution of elements, so we can calculate the average –

(2 + 1 + 14
+ 11) / 4 = 28/4 = 7

Taking an
average of the positions of the letters in the word is another way to code it.

###
**Use Reasoning Tricks for Solving
these Coding and Decoding Problems **

Question 1:
In a certain code BOARD is written as CNBQE. How is CRIME written in that code?

1)
DSJNF 2) BQHLD 3) DQJLF 4) BSHND 5) None of these

Question 2:
In a certain code KNIFE is written as $3%#5 and LAKE is written as 7@$5. How is
FAIL written in that code?

1) %$#7 2) #@%7 3) $@%7 4) $%@7 5) None of these

Question 3:
In a certain code language ‘CAT’ is written as ‘3120’ and ‘DOG’ is written as
‘4157’. What will be the decoded form of ‘25144’?

1) BEND 2) BEADD 3) YADD or YND 4) Cannot be determined 5) None of these

Remember to
write your answers in the comments section!

Keep
practicing, because the more you practice, the better you’ll get with
identifying and using reasoning tricks!

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