Wednesday, 19 April 2017

How to Easily Solve Algebra Problems in Few Seconds for IBPS PO Exam

The Substitution Method is extremely useful when you have to solve algebra problems in IBPS PO Exam


Innumerable algebra problems are asked in all competitive exams like IBPS PO, which makes it a very important topic. Algebra problems can be both confusing and time taking. The substitution method comes in very handy here because not only is it quick but also simple.
So in the 22nd blog posts in the series of smart methods that will help you solve questions in 5- 10 seconds, this smart method will simplify algebra problems like never before!
algebra problems

Algebra Problems

We all know algebra is a part of mathematics where alphabets are used as variables to represent numbers and quantities in expressions, formulas and equations. Algebra problems can be a combination of any of these mentioned things and usually need you to determine or find the value of an expression or variable.

Example of Algebra Problems

If the value of a + b + c= 0, then find the value of   a²⁄bc + b²⁄ca + c²⁄ab

Conventional method to Solve Algebra Problems

The regular method to solve a  question like uses lots of algebraic formulas, substitution and many steps to get the right answer.
a + b + c= 0
Step 1:
a + b= - c

Step 2:
Cubing the expression (a + b)3 = -c3

Step 3:
a3 + b3 + 3ab (a+b) = -c3

Step 4:
a3 + b3 + c3 = 3abc

Step 5:
(a3 + b3 + c3)/abc = 3

Step 6:
(a3/abc) + (b3/abc) + (c3/abc) = 3

Step 7:
(a2/ bc) + (b2/ac) + (c2/ab) = 3

The correct answer but after tons of steps and unlike school no one cares about the steps but about the correct answer.


Smart Method to Solve Algebra Problems

Substitution Method is the key to all short cuts in any algebraic expression. In the above expression arrive at a number combination which after substitution will add upto zero.
For example, 
Step 1:
Let a= 2, b= -1, c= -1, these values will satisfy the given expression, 2 -1 -1 = 0

Step 2:
Substituting the given values in the expression -  a²⁄bc + b²⁄ca + c²⁄ab
[2²/ (-1) (1)] + [(-1)²/ (-1) (2)] + [(-1)²/ (-1) (2)]

Step 3:
(4/1) + (-1/2) + (-1/2) = 3

Two steps, no algebraic formulas and still the correct answer that too in 5 seconds!
algebra problems

See our expert faculty explain the substitution method in the video.


Solve these algebra problems by using the substitution method-

Question 1: If a ⁄b = c ⁄d = e ⁄f  = 3, then  (2a² + 3c² + 4e²) ⁄ ( 2b² + 3d² + 4f ²)= ?
1) 2      2) 3      3) 4      4) 9      5) None of these

Question 2: If x= 4ab ⁄ (a+b) then  (x+ 2a) ⁄ (x-2a) + (x+ 2b) ⁄ (x-2b) = ?
1) a      2) b      3) 0      4) 2      5) None of these


Remember to leave your answer in the comments along with the time saved on using the substitution method.

For more smart methods, stay tuned for more and keep practicing. 
algebra problems

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