###
**Questions about number series that
deal with consecutive numbers find their way in all competitive exams. Read
this post to solve such questions the smart way.**

While on one hand problems on Number Series can be mind boggling and leave you confused and on the other hand consecutive number problems are asked in all competitive exams like SBI PO, IBPS, SSC and many more. So it’s time we address this problem and discuss a simple and effective way to solve consecutive number problems easily.

So here is
the 16

^{th}blog posts in the series of smart methods that will help you solve questions in 5- 10 seconds that would otherwise take 30- 45 seconds.###
**Consecutive Number Problems**

Problems
based on number series may look to be confusing and difficult but don’t let
them deceive you because it is actually one of the easiest topic of competitive
exams if approached in the right way. In such questions numbers will be
connected to each other by a common pattern and you have to identify the
numbers. Patterns can be odd numbers, even numbers, multiples of a certain
number, square, cubes and so on.

###
**Example of Consecutive Number Problems**

The
sum of 5 consecutive odd numbers is 575. What will be the sum of the next set
of 5 consecutive odd numbers?

1) 625 2) 580 3) 600
4) 650 5) None of these

###
**Conventional Method to Solve Consecutive
Number Problems**

The usual
way to approach a problems on number series is like this is by assuming the
first number in the series to be ‘y’ based on this the next 4 numbers will be :
y+2, y+4, y+6, y+8

This will
lead us to the equation

**Step 1:**

y + (y+2) +
(y+4) + (y+6) + (y+8) = 575

**Step 2:**

5y + 20 =
575

**Step 3:**

5y = 555

**Step 4:**

y = 111

**Step 5:**

Therefore
the 5 numbers are: 111, 113, 115, 117, 119

**Step 6:**

Therefore
the next 5 numbers will be: 121, 123, 125, 127, 129

**Step 7:**

Adding these
we’ll get 675

###
**Smart Method to Solve Consecutive
Number Problems**

The above
method is simple and straight forward but has just too many steps and
calculations; this may actually make you skip such a simple question. But, you
can easily solve such number series by using this simple 2 step method and
almost zero amount of calculation.

Let us assume
a, b, c, d, e, f, g, h, l and j as the ten consecutive odd numbers where a-e
are Set 1 and f-j are Set 2.

We can
conclude that-

**Step 1:**

f = a+ 10 (as
the difference between each consecutive odd number is 2)

**Step 2:**

Similarly,
g= b+10, h=c+10, i=d+10, j=e+10

**Step 3:**

f + g+ h+ i+
j = a+ b+ c+ d + e + 50 = 575 + 50

**Step 4:**

f + g+ h+ i+
j = 625

Steps go
down by almost half and calculation just disappears and we reach our answer in
about 7 seconds, a total win win situation!

See our
expert faculty explain this smart method to you!

Solve the
following consecutive number problems using the smart method you just saw.

Question 1: The
sum of 3 consecutive odd numbers is 256. What will be the sum of the next set
of 3 consecutive odd numbers?

1) 274 2) 280 3) 300 4) 350 5) None of these

Question 2: The
sum of five consecutive even numbers is 600. What is the sum of the next set of
the consecutive even numbers?

1) 400 2)
650 3) 600 4) 550 5) None of these

Do write your answers in
the comment section below and remember to tell us how many seconds you took to
solve these questions on number series.

Watch out
this space for more smart methods!

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