Questions about number series that deal with consecutive numbers find their way in all competitive exams. Read this post to solve such questions the smart way.
While on one hand problems on Number Series can be mind boggling and leave you confused and on the other hand consecutive number problems are asked in all competitive exams like SBI PO, IBPS, SSC and many more. So it’s time we address this problem and discuss a simple and effective way to solve consecutive number problems easily.
So here is the 16th blog posts in the series of smart methods that will help you solve questions in 5- 10 seconds that would otherwise take 30- 45 seconds.
Consecutive Number Problems
Problems based on number series may look to be confusing and difficult but don’t let them deceive you because it is actually one of the easiest topic of competitive exams if approached in the right way. In such questions numbers will be connected to each other by a common pattern and you have to identify the numbers. Patterns can be odd numbers, even numbers, multiples of a certain number, square, cubes and so on.
Example of Consecutive Number Problems
The sum of 5 consecutive odd numbers is 575. What will be the sum of the next set of 5 consecutive odd numbers?
1) 625 2) 580 3) 600 4) 650 5) None of these
Conventional Method to Solve Consecutive Number Problems
The usual way to approach a problems on number series is like this is by assuming the first number in the series to be ‘y’ based on this the next 4 numbers will be : y+2, y+4, y+6, y+8
This will lead us to the equation
y + (y+2) + (y+4) + (y+6) + (y+8) = 575
5y + 20 = 575
5y = 555
y = 111
Therefore the 5 numbers are: 111, 113, 115, 117, 119
Therefore the next 5 numbers will be: 121, 123, 125, 127, 129
Adding these we’ll get 675
Smart Method to Solve Consecutive Number Problems
The above method is simple and straight forward but has just too many steps and calculations; this may actually make you skip such a simple question. But, you can easily solve such number series by using this simple 2 step method and almost zero amount of calculation.
Let us assume a, b, c, d, e, f, g, h, l and j as the ten consecutive odd numbers where a-e are Set 1 and f-j are Set 2.
We can conclude that-
f = a+ 10 (as the difference between each consecutive odd number is 2)
Similarly, g= b+10, h=c+10, i=d+10, j=e+10
f + g+ h+ i+ j = a+ b+ c+ d + e + 50 = 575 + 50
f + g+ h+ i+ j = 625
Steps go down by almost half and calculation just disappears and we reach our answer in about 7 seconds, a total win win situation!
See our expert faculty explain this smart method to you!
Solve the following consecutive number problems using the smart method you just saw.
Question 1: The sum of 3 consecutive odd numbers is 256. What will be the sum of the next set of 3 consecutive odd numbers?
1) 274 2) 280 3) 300 4) 350 5) None of these
Question 2: The sum of five consecutive even numbers is 600. What is the sum of the next set of the consecutive even numbers?
1) 400 2) 650 3) 600 4) 550 5) None of these
Do write your answers in the comment section below and remember to tell us how many seconds you took to solve these questions on number series.
Watch out this space for more smart methods!