Recruitment as a probationary officer in a bank is the aspiration of lakhs of young graduates. That calls for the development of the ability and skill to ace the aptitude tests, especially the quantitative aptitude tests that are a part and parcel of the recruitment process in banks.

Percentage problems are an integral part of such tests. Rohit Agarwal, the expert faculty at TalentSprint shows you an easy and smart way to solve percentage based problems. He refers to these as ‘Super Techniques’ and that is truly an apt description for such methods.

### An Illustration:

“If A’s salary is 25% more than that of B, then by what percentage is B’s salary less than that of A?”

The first option offered to the student will be 25% and that will be selected by a the large majority of students. But, it will be an erroneous selection.

Remember that when 30 increases to 60, it is a 100% increase but when 60 reduces to 30, it is a 50% reduction. Though the change in absolute values is the same, percentage values change. There will be students who will work out the problem in a conventional way and arrive at the right option but that method will take a lot of time. TalentSprint uses a ‘Super Technique’ that points to the right answer in a matter of seconds. Always remember that time is critical in a banking career exam.

### The Super Technique

We know that 25% is equal to ¼. We also know that B’s salary is less than that of A so the fraction that represents the percentage by which B’s salary is less than A has to be less than ¼.

A fraction can be reduced by either reducing the numerator or increasing the denominator. In these problems, the numerator is never altered. We increase the denominator to arrive at the answer. The question is – By how much? Simple. Increase the denominator by the value of the numerator. In the illustration, the denominator should be increased by 1, from 4 to 5. The fraction then becomes 1/5 which converts to 20% in terms of percentage and that is the answer. B’s salary is less than A’s salary by 20%.

If the problem states – A’s salary is 50% less than B’s salary. By what percentage is B’s salary more than that of A, then remember that since B’s salary is more, the denominator of the fraction representing the given percentage i.e. ½ should be reduced. By how much? – By the value of the numerator i.e. 1. The fraction for B becomes 1/1 or 100%.

Watching is better than reading. Watch how Rohit Agarwal cracks the percentage problems for you in a jiffy.

These and many more ‘super techniques’ are disclosed in the 400+ video lessons which you can watch by joining TalentSprint LIVE Online Coaching.

Such a nice video..which is very helpful

ReplyDeleteSuch a nice video..which is very helpful

ReplyDeletevery helpful technique sir......

ReplyDelete